Optimal. Leaf size=66 \[ \frac{5 \sin ^3(a+b x)}{6 b}+\frac{5 \sin (a+b x)}{2 b}+\frac{\sin ^3(a+b x) \tan ^2(a+b x)}{2 b}-\frac{5 \tanh ^{-1}(\sin (a+b x))}{2 b} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.0469644, antiderivative size = 66, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.235, Rules used = {2592, 288, 302, 206} \[ \frac{5 \sin ^3(a+b x)}{6 b}+\frac{5 \sin (a+b x)}{2 b}+\frac{\sin ^3(a+b x) \tan ^2(a+b x)}{2 b}-\frac{5 \tanh ^{-1}(\sin (a+b x))}{2 b} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 2592
Rule 288
Rule 302
Rule 206
Rubi steps
\begin{align*} \int \sin ^3(a+b x) \tan ^3(a+b x) \, dx &=\frac{\operatorname{Subst}\left (\int \frac{x^6}{\left (1-x^2\right )^2} \, dx,x,\sin (a+b x)\right )}{b}\\ &=\frac{\sin ^3(a+b x) \tan ^2(a+b x)}{2 b}-\frac{5 \operatorname{Subst}\left (\int \frac{x^4}{1-x^2} \, dx,x,\sin (a+b x)\right )}{2 b}\\ &=\frac{\sin ^3(a+b x) \tan ^2(a+b x)}{2 b}-\frac{5 \operatorname{Subst}\left (\int \left (-1-x^2+\frac{1}{1-x^2}\right ) \, dx,x,\sin (a+b x)\right )}{2 b}\\ &=\frac{5 \sin (a+b x)}{2 b}+\frac{5 \sin ^3(a+b x)}{6 b}+\frac{\sin ^3(a+b x) \tan ^2(a+b x)}{2 b}-\frac{5 \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\sin (a+b x)\right )}{2 b}\\ &=-\frac{5 \tanh ^{-1}(\sin (a+b x))}{2 b}+\frac{5 \sin (a+b x)}{2 b}+\frac{5 \sin ^3(a+b x)}{6 b}+\frac{\sin ^3(a+b x) \tan ^2(a+b x)}{2 b}\\ \end{align*}
Mathematica [A] time = 0.185798, size = 52, normalized size = 0.79 \[ \frac{(24 \cos (2 (a+b x))-\cos (4 (a+b x))+37) \tan (a+b x) \sec (a+b x)-60 \tanh ^{-1}(\sin (a+b x))}{24 b} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A] time = 0.022, size = 79, normalized size = 1.2 \begin{align*}{\frac{ \left ( \sin \left ( bx+a \right ) \right ) ^{7}}{2\,b \left ( \cos \left ( bx+a \right ) \right ) ^{2}}}+{\frac{ \left ( \sin \left ( bx+a \right ) \right ) ^{5}}{2\,b}}+{\frac{5\, \left ( \sin \left ( bx+a \right ) \right ) ^{3}}{6\,b}}+{\frac{5\,\sin \left ( bx+a \right ) }{2\,b}}-{\frac{5\,\ln \left ( \sec \left ( bx+a \right ) +\tan \left ( bx+a \right ) \right ) }{2\,b}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [A] time = 0.959911, size = 89, normalized size = 1.35 \begin{align*} \frac{4 \, \sin \left (b x + a\right )^{3} - \frac{6 \, \sin \left (b x + a\right )}{\sin \left (b x + a\right )^{2} - 1} - 15 \, \log \left (\sin \left (b x + a\right ) + 1\right ) + 15 \, \log \left (\sin \left (b x + a\right ) - 1\right ) + 24 \, \sin \left (b x + a\right )}{12 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [A] time = 1.76429, size = 231, normalized size = 3.5 \begin{align*} -\frac{15 \, \cos \left (b x + a\right )^{2} \log \left (\sin \left (b x + a\right ) + 1\right ) - 15 \, \cos \left (b x + a\right )^{2} \log \left (-\sin \left (b x + a\right ) + 1\right ) + 2 \,{\left (2 \, \cos \left (b x + a\right )^{4} - 14 \, \cos \left (b x + a\right )^{2} - 3\right )} \sin \left (b x + a\right )}{12 \, b \cos \left (b x + a\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A] time = 1.22717, size = 92, normalized size = 1.39 \begin{align*} \frac{4 \, \sin \left (b x + a\right )^{3} - \frac{6 \, \sin \left (b x + a\right )}{\sin \left (b x + a\right )^{2} - 1} - 15 \, \log \left ({\left | \sin \left (b x + a\right ) + 1 \right |}\right ) + 15 \, \log \left ({\left | \sin \left (b x + a\right ) - 1 \right |}\right ) + 24 \, \sin \left (b x + a\right )}{12 \, b} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]